Question

a man deposited Rs.10,000 on saving account at 5%p.a interest compounded yearly and another sum on fixed deposit account at 8%p.a interest compounded half early. After one year the interest on fixed deposit account was Rs.152.80 more than the interest on the saving account, find the total amount of money in his two accounts at the end of the year.​

Answer 1

Answer:

According to the given question

Intersect per year =10,000×5 %

=10,000×

100

5

=500

Now,

Amount in I

st

years =10,000

Amount in 2

nd

year =10,000+intersect

=10,000+500=10,500

Amount in 3

rd

year =10,500+Intersect

=10,500+500=11,000

Then our series becomes

10,000,10,500,11000.

This is an AP

where a=10,000

d=10,500−10,000=500

time (n)=15 year

Then,

Amount in 15

th

year =a+(n−1)d

=10,000+(15−1)×500

=10,000+14×500

10,000+7000

17,000

Thus amount in 15

th

year in Rs.17,000

Amount of per 20 year =a

n

=a+(n−1)d

10,000+(21−1)×500

10,000+10,000

20,000

Thus, the amount in 20

th

years is

Rs.⇒20,000/−

Hence, this is the answer.