a man deposited Rs 80000 in a bank which pays him 6% interest after 3 years he withdraws the money and buys a car for rs 90000. how much money is left with him
Answers
Answered by
0
P= 80000
R= 6
T=3
= P ×R×T/100
= 80000×6×3/100
=144000
Now, he bought car of Rs 90000
Therefore, =14000-90000
= 54000
Rupee left = 54000
R= 6
T=3
= P ×R×T/100
= 80000×6×3/100
=144000
Now, he bought car of Rs 90000
Therefore, =14000-90000
= 54000
Rupee left = 54000
Answered by
1
According to me
P=80000rs
R=6%
T=3yrs
If you do yearly then
For first year
I=P*R*T/100
80000*6*1/100=4800
Ci=4800+80000=84800
For second year
I=P*R*T/100
84800*6*1/100=5088
CI=5088+84800=89888
For third year
I=P*R*T/100
89888*6*1/100=5392.28
CI=5392.28+89888=95280.28
If he purchase car for 90000 then
Rs left=95280.28-90000=5280.28 Rs left for man
Thanku yo
P=80000rs
R=6%
T=3yrs
If you do yearly then
For first year
I=P*R*T/100
80000*6*1/100=4800
Ci=4800+80000=84800
For second year
I=P*R*T/100
84800*6*1/100=5088
CI=5088+84800=89888
For third year
I=P*R*T/100
89888*6*1/100=5392.28
CI=5392.28+89888=95280.28
If he purchase car for 90000 then
Rs left=95280.28-90000=5280.28 Rs left for man
Thanku yo
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