Question

A man deposits in a bank 20/- in the first month , 30/- in the second month , 40/- in the third month and so on .What will be the amount deposited by him at the end of 2yrs?

Answer 1

Answer:

In the first year amount deposited=900

Amount deposited in the second year=900×2=1800

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Answer 2

Answer

This can be solved by treating it as an arithmatic progression with:

First term, a=20

total terms, n=24

and common difference, d=10

Using the formula for Sum, S

S= n/2[2a+ (n-1)d]

=24/2[2x20+ (24-1)10]

=12[40+230]

=12x270

=3240.