Math, asked by ayanjain187, 1 month ago

A man deposits Rs. 200 per month in a recurring deposit account at 9p.a and earned a total interest of Rs. 1764

Answers

Answered by bhagyashreechowdhury
11

Complete Question:

A man deposits Rs. 200 per month in a recurring deposit account at 9% p.a and earned a total interest of Rs. 1764. How many monthly deposits does the man pay?​

Given:

A man deposits Rs. 200 per month in a recurring deposit account at 9p.a and earned a total interest of Rs. 1764.

To find:

How many monthly deposits does the man pay?​

Solution:

The monthly deposit of the man = Rs. 200

The rate of interest, R = 9%

The total interest earned = Rs. 1764

Let "n" represents the no. of months the monthly deposits are to be paid.

The total money deposited is,

= [Monthly amount] × [number of months]

= Rs. 200 × n

= Rs. 200n

Also,

The principal for 1 month will be = 200 \times \frac{n(n+1)}{2} = 100n(n+1) = 100n^2 + 100n

We know,

\boxed{\bold{S.I. =  Principal \:for\:1\:month \times \frac{ R}{12 }\times \frac{1}{100}  }}

Therefore, by using the above formula, we get the equation as,

1764 =  (100n^2 + 100n) \times \frac{ 9}{12 }\times \frac{1}{100}  }}

\implies 1764 = 100 (n^2 + n) \times \frac{ 9}{12 }\times \frac{1}{100}

\implies n^2 + n = \frac{1764 \times 12 }{9}

\implies n^2 + n = 2352

\implies n^2 + n - 2352 = 0

\implies n^2 + 49n -48n - 2352 = 0

\implies n(n+49) - 48 (n + 49) = 0

\implies (n+49)  (n - 48) = 0

\implies n= -49 \:or\: n = 48

since no. of months cannot be negative

\bold{n = 48}

Thus, the man paid 48 monthly deposits.

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