Question

a man deposits rs 25000 for 2 years at the annual rate of 6 % in the P N B. howmuch interest will the bank pay to him? ​

Answer 1

Here P=25000, T or n=2, R=6%, i=6/100=.06

Incase of Simple Interest

S.I=PTR/100

=(25,000×2×6)/100

=Rs3000

In case of Compound Interest

C.I=P(1+I)ⁿ -1

=25,000[(1+.06)²-1]

=25,000[(1.06)²-1]

=25,000(1.1236-1)

=25,000×.1236

=Rs3090

(Ans)

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Answer 2

Answer:-

$\pink{\bigstar}$ The bank will pay the interest of a $\large\leadsto\boxed{\tt\red{Rs. \: 3000}}$

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• Given:-

• A man deposits Rs. 25000 in bank.

• Time = 2 years

• Rate = 6% p.a

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• To Find:-

• Interest to be payed by the bank.

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• Solution:-

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{S.I = \dfrac{P \times R \times T}{100}}}}$

where,

• S.I = Simple Interest

• P = Principal amount

• R = Rate

• T = Time period

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• Substituting in the Formula:-

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➪ $\sf S.I = \dfrac{25000 \times 6 \times 2}{100}$

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➪ $\sf S.I = 250 \times 6 \times 2$

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➪ $\sf S.I = 250 \times 12$

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★ $\large{\bf\purple{S.I = 3000}}$

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Therefore,the total amount he will get will be:-

✯ PRINCIPAL + INTEREST

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➪ $\sf 25000 + 3000$

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★ $\large{\bf\purple{Rs. \: 28000}}$

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Hence, the bank will pay him interest of Rs. 3000 and the total amount will be Rs. 28000