a man deposits rupees 1200 in a bank at the end of each year @ 5% p.a C.I what would be his deposit after 15 years
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Answered by
0
Answer:
- P =1200
- R =5 %
- T = 15yrs
- Amt = p(1+ r/100)*n
- = 1200( 1+ 5/100 )*15
- = 1200(21/20 )*15
- after this solve yourself
- because on C I and S I time perid maximum 5yrs
Answered by
0
Answer:
P =Rs 1200
r = 5%
i = 5÷100
n = 15 years
w/k
A = P/i {(1 + i)n - 1}
A = 1200/0.05 { (1 + 0.05)¹⁵ - 1}
A = 24000 {( 1.05)¹⁵ - 1
A = 24000 ( 2.0789 - 1 )
A = 24000 × 1.0789
A = 25893.6
Therefore A = Rs 25893.6
Ans ..
Explanation:
(1.05)¹⁵
= 15 × log1.05
= 2.0789
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