Question

A man' distributed his property among his three sons
and wife. He gave 1/5 of his whole property to his
1/3
eldest son,
of the rest to his second son. of the
3/8
rest to his third son and the rest to his wife. If his
wife got Rs. 1200, find his whole property.
​

Answer 1

Answer:

3600 Rs.

Step-by-step explanation:

Let his property be x.

Therefore,

Property given to eldest son = $\frac{1}{5} x$

Property left = $x - \frac{1}{5} x$ =$\frac{5x - x}{5}$ = $\frac{4}{5} x$

Now, Property given to the second son = $\frac{1}{3} * \frac{4}{5}x$ = $\frac{4}{15}x$

Property left = $\frac{4}{5}x - \frac{4}{15}x$ =$\frac{60x - 20x}{75}$ = $\frac{40}{75}x$ = $\frac{8}{15} x$

Now, Property given to the third son = $\frac{3}{8} * \frac{8}{15} x$ = $\frac{1}{5} x$

Property left = $\frac{8}{15} x - \frac{1}{5} x$ = $\frac{40x - 15x}{75}$ = $\frac{25}{75} x$ = $\frac{1}{3} x$ = Property given to the wife

Therefore, $\frac{1}{3} x = 1200$ ⇒ $x = 1200 * 3$ ⇒ x = Rs. 3600