A man distributed some amount among children.If there were 3 children less everyone would have got 60 rupees more. However if he had 2 more children each one would have got Rs.20 less. Find no. of children and amount recieved by them.
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let the number of children be = x
and the amount recieved by them be = y
if there were 3 children less :
(x - 3) = ( y +60)
solving this equation we get
x - y = 57 -------------- (1)
if 2 childern more :
(x+3) = (y-20)
solving this equation we get
x - y = - 23 -------------- (2)
solve these equations by any meathod you wish
and you will get the right answer
and the amount recieved by them be = y
if there were 3 children less :
(x - 3) = ( y +60)
solving this equation we get
x - y = 57 -------------- (1)
if 2 childern more :
(x+3) = (y-20)
solving this equation we get
x - y = - 23 -------------- (2)
solve these equations by any meathod you wish
and you will get the right answer
AdithiPatel:
hope it helps you
Answered by
1
let the number of children be = x
and the amount recieved by them be = y
if there were 3 children less :
(x - 3) = ( y +60)
x - y = 57 -------------- (1)
if 2 childern more :
(x+3) = (y-20)
x - y = - 23 -------------- (2)..
Please mark it as brainiest answer .............
and the amount recieved by them be = y
if there were 3 children less :
(x - 3) = ( y +60)
x - y = 57 -------------- (1)
if 2 childern more :
(x+3) = (y-20)
x - y = - 23 -------------- (2)..
Please mark it as brainiest answer .............
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