Question

A man divided an amount between his two sons in the ratio of their ages.The sons received 48000 and 54000.If one son is 5 year older than the other,find the age of younger son

Answer 1

Answer:

Step-by-step explanation:

let the ages of the sons be x and y

x=y+5 (equation 1)

x/y= 48000/54000=8/9

x/y=8/9 ⇒ 9x=8y(equation 2)

substituting equation 1 in equation 2

9(y+5)=8y ⇒ 9y+45=8y ⇒y=45

x=y+5 = 45+5 = 50=x

so,the age of younger son=45 years

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Answer 2

Step-by-step explanation:

Let the son’s ages be ‘x’ years and ‘y’ years

Given, x - y = 5

⇒ x = y + 5

Now,

Ratio of their shares = ratio of their ages

⇒ 54000 ∶ 48000 = x ∶ y

⇒ 9 ∶ 8 = (y + 5) ∶ y

⇒ 9y = 8y + 40

⇒ y = 40

∴ The younger son’s age is 40 years

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