Question

A man divided his property to three son and wife he gave 1/5 to whole properties to first son , remender properties 1/3 second son and remen property 3/8 third son and wife gave 00 find his total property

Answer 1

Given:

A man divides his property like

• 1/5 to whole properties to first son

• Remainder of properties 1/3 to second son

• Remainder of properties 3/8 to third son

• And to wife he gave ₹00.

To find:

Total property of the man.

Solution:

1) Let the total property of the man is ₹120 (which is LCM of 5, 3, 8 this make the question easy to solve)

2) 1/5 to whole properties to first son means 1/5 of 120 = ₹24

3) Remainder of properties 1/3 to second son means

• 1/3 of (120-24) = 1/3 of 96 = ₹32

4) Remainder of properties 3/8 to third son means

• 3/8 of (96-32) = 3/8 of 64 = ₹24

5) So money left for his wife would be 64-24 = ₹40.

6) But according to the question the wife get ₹00

• so 40 >> 0

•      1   >> 0/40

•  120  >> 0×120

• property is ₹00

Total property of the man is ₹00.