Math, asked by Aadityarajak4459, 8 months ago

A man divided his savings as follows: wife 30%, first son 25% ,second son and daughter 15% each, youngest son 50% of the remainder and the rest of his brother received sh.60,000. How much did each of the others receive?

Answers

Answered by bktbunu
2

Step-by-step explanation:

savings for wife, first son, second son and daughter = 30%+25%+15%+15% = 85%

left = 100%-85% = 15%

savings for youngest son = 50% of 15% = (50/100) × 15% = 7.5%

left = 15% - 7.5% = 7.5% = savings for brother = 60000

=> 7.5% = 60,000

=> 100% = 60,000 × 100 / 7.5 = 8,00,000

savings for wife = 800000 × 30% = 2,40,000

savings for first son = 800000 × 25% = 2,00,000

savings for second son = 800000 × 15% = 1,20,000

savings for daughter = 800000 × 15% = 1,20,000

savings for youngest son = 800000 × 7.5% = 60,000

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