Question

A man divided Rs.25000 among his four sons A, B, C and D in such a way that A got 4 parts, B got 6 parts, C got 7 parts and D got 3 parts. What percentage of the total amount did C get?

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Answer 1

$\texttt {Let the money given to A, B, C and D}$

$\texttt{be 4x, 6x, 7x and 3x.}$

$\texttt{A/q}$

$\mathtt{4x+6x+7x+3x = 25000}$

$\implies \mathtt{20x = 25000}$

$\implies \mathtt{x = \large \frac{25000}{20}}$

$\implies \mathtt{x = 1250}$

$\therefore \texttt{ The amount that C got = 7×1250}$

$\texttt{ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 8750}$

$\mathtt{ The \; \% \; of \; money \; C \; got \; = \frac{8750}{25000} × 100\%}$

$\mathtt{ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 35\%}$