Question

a man divided the two sums of money among four sons R ,S ,T, U the first ratio 4 : 3 :2 :1 and second in the ratio 5 :6 :7 :8 .if second sum of money is twice of a sum of money is twice first sum which son receives the largest part​

Answer 1

Answer:

Step-by-step: so what can I do?

Answer 2

Answer:

Step-by-step explanation:

First sum ratio 4:3:2:1

Let consider it to be proportionate of x

=4x+3x+2x+x

=10x

Second sum ratio 5:6:7:8

ler consider it to be proportionate of y

=5y+6y+7y+8y

=26y

Second sum money is twice as first sum

=>26y=(2×10x)

=>x=1.3y

4×1.3y=5.2y 3×1.3y=3.9y 2×1.3y=2.6y 1.3y

5y 6y 7y 8y

10.2y 9.9y 9.6y 9.3y

R S T U

R is receiving largest total