a man divided the two sums of money among four sons R ,S ,T, U the first ratio 4 : 3 :2 :1 and second in the ratio 5 :6 :7 :8 .if second sum of money is twice of a sum of money is twice first sum which son receives the largest part
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Step-by-step: so what can I do?
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Step-by-step explanation:
First sum ratio 4:3:2:1
Let consider it to be proportionate of x
=4x+3x+2x+x
=10x
Second sum ratio 5:6:7:8
ler consider it to be proportionate of y
=5y+6y+7y+8y
=26y
Second sum money is twice as first sum
=>26y=(2×10x)
=>x=1.3y
4×1.3y=5.2y 3×1.3y=3.9y 2×1.3y=2.6y 1.3y
5y 6y 7y 8y
10.2y 9.9y 9.6y 9.3y
R S T U
R is receiving largest total
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