Question

a man divides a certain part of land equally between two offspring a and b for agriculture. they produce radish and carrot. the man found that the ratio between radish and carrot land on the whole land is 7:5. if a produces radish at only 60% of his land then find what percentage part b land produces carrot

Answer 1

Answer:

$42.86 \: \%$

Step-by-step explanation:

Let percentage part of b land = X %

so,

$\frac{7}{5} = \frac{60}{x } \\ x = \frac{60 \times 5}{7} \\ x = \frac{300}{7} \\ x = 42.86$

So, percentage part of b land = 42.86 %

Answer 2

n = 42.85

Let the land divided to 'a' be = x

and the land divided to 'b' be = y

The ratio between radish and carrot grown on the land is 7 : 5

percentage of radish produced be = 60%

let percentage of b land produces carrot be 'n'

As,

x = y

⇒  $\frac{7}{5} = \frac{60}{n}$

⇒  7n = 60 x 5

⇒  7n = 300

⇒   n = 42.85

Therefore, the part of percentage of land 'b' used to produce carrot is  

42.85

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