Physics, asked by arzookamboj19, 9 months ago

. A man does 800 J of work in lifting a 40 kg bucket from
a well. Calculate the depth of the well.
(Take g = 10 m s-2) ​

Answers

Answered by bhanuprakashreddy23
16

Answer:

given,

work done=800J

mass of the bucket=40kg

g=10ms^-2

now,

w=F.S(w=workdone,F=force,s=displacement)

w=ma.s(F=ma)

800=40(10).h

800=400.h

h=800÷400

h=2m

Answered by lavishagarg48154
3

Answer..

work done=800J

mass=40kg

g=10ms-2

w=m*a*s

800=40*10*h

h=800/400

=2m

Similar questions
Math, 9 months ago