Question

A man does a given amount of work in 10 sec. Another man does the same amount of work in 20 sec. The ratio of the output power of first man to the second man is ta A. 2/1 B.1/2 C.1 D. 4/1 ​

Answer 1

Answer:

1:2

Explanation:

Given

Man works for 10sec

Other Man works for 20sec

So, 10/20

=1:2

Answer 2

Answer:

Output power ratio of first man to the second man = 1/2

Explanation:

Given:-

Work done by man in 10 seconds = A (let)

Work done by man in 1 second = A/10

Also,

Work done by another man in 20 seconds = B (let)

Work done by another man in 1 second = B/20

Now, finding the output ratio of both man:-

Output Ratio = A/ 10 / B/ 20

= A/10 × 20/B

= 20A / 10B

= 2A / B

B = 2A

B/A = 2/1

A/B = 1/2 (On reversing)

Hence, the output power ratio of the first man to the second man is 1/2.

Hope it helps! :-))