Question

a man donated 1/10th of his money to a school, 1/6th of the remaining to a church and the remaining money he distributed equally among his three children. if each child gets ₹50000, how much money did the man originally have ?​

Answer 1

Answer:

Let the money the man originally have be x

He donates 1/10 to a school

1/10 × x = x/10

Remaining money = x - x/10

= 9x/10

He donates 1/6 to a church from the remaining money,

1/6 × 9x/10 = 3x/20

Remaining money = 9x/10 - 3x/20

= 12x/20

= 3x/4

the remaining money he distributed equally among his three children

= 3(x/4)

So,each child gets x/4 amount.

According to the question,

If each child gets 50000 ,

x/4 = 50000

x = 200000

So the amount of money which the man originally have is 2,00,000.

Hope it helps

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Answer 2

Step-by-step explanation:

answer is 2,00,000. so answer is ready for you