a man donated 1 by 10 of his money to a school one by sixth of the remaining to a church and remaining money he distributed equally among his three children and if child gets rupees 50000 how much money did the Man original have
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Such probems can be solved either by percentage theory or using algebra..
We assume he has Rs X
1/10 of X = X/10 donated to school
1/6 of X = X/6 donated to church
So, remaining =
X - (X/10 + X/6 )
= X - (16X/60 )
= 44X/60 was distributed among 3 chidren
So, each gets (44X/60) ÷3
=> 11X/45 = 50000
=> 11X = (50,000 * 45 )
=> X = 20,4545.45…
He originally had Rs 20,4545 ( approx)
We assume he has Rs X
1/10 of X = X/10 donated to school
1/6 of X = X/6 donated to church
So, remaining =
X - (X/10 + X/6 )
= X - (16X/60 )
= 44X/60 was distributed among 3 chidren
So, each gets (44X/60) ÷3
=> 11X/45 = 50000
=> 11X = (50,000 * 45 )
=> X = 20,4545.45…
He originally had Rs 20,4545 ( approx)
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