A man drives 150km from a to b in 3 hrs and 20min and return in 4 hrs and 10 min.is s is the average speed of the entire trip then the averge for the journey from a to b exceeds s by
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40 km/h is the right answer
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Suppose Man drives From A to B (i.e 150 Km) in 3 hours 20 minutes (i.e 3 + 1/3 = 10/3 hours) then Speed is 150/(10/3) = 45km/hr. Now again he drives from B to A (same 150 km) in 4 hours 10 minutes (i.e 4+1/6 = 25/6 hr) then speed = 150/(25/6) = 36km/hr. Now Average Speed is (45+36)/2 = 40.5 km/hr. Question is to find avergae speed exceeds Speed from to by (i.e from A to B by) which is 45 - 40.5 = 4.5km/hr.
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