A man drives a car of distance of 200km at an average speed of 44km/hr. what must be his average speed for the next 20km if he is to cover the total distance in 9hrs
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D1=200km
V1=44km/hr
T1=50/11hr
D2=200+20=220km
T2=9hrs
V2=20/9 m/sec
T1/T2=V2/V1=D1/D2
By solving we get
V2=2.2m/sec
Hope it helps you
Mark it the brainest
V1=44km/hr
T1=50/11hr
D2=200+20=220km
T2=9hrs
V2=20/9 m/sec
T1/T2=V2/V1=D1/D2
By solving we get
V2=2.2m/sec
Hope it helps you
Mark it the brainest
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