A man drives his car with uniform speed from A to the place B which is 150km away. Again he returns to the place A by increasing the speed of the car 10km/hr there by reached 30min earlier then the taken in the forward journey. Find the total time taken by him in forward journey?
Answers
Step-by-step explanation:
Given
A man drives his car with uniform speed from A to the place B which is 150 km away . Again he returns to the place A by increasing the speed of the car 10 km/hr there by reached 30 min earlier then the taken in the forward journey. Find the total time taken by him in forward journey?
Distance = 150 km
Let the original speed be x
Now increased speed will be x + 10
Now time = 150 / x
= 150 / x + 10
Now according to question we get
150 / x – 150 / (x + 10) = 1/2
150 x + 1500 – 150 x / x(x + 10) = 1/2
3000 = x(x + 10)
So x^2 + 10 x – 3000 = 0
So x^2 + 60 x – 50 x – 3000 = 0
So x (x + 60) – 50 (x + 60) = 0
So (x + 60) (x – 50) = 0
Or x = 50
Now original speed will be 50 km /hr and increased speed will be (50 + 10) = 60 km/hr
Also time will be 150 / 50 = 3 hours
New time will be 150/60 = 2.5 hours
So total time taken will be 5.5 hours
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