Question

A man drives his car with uniform speed from place A to the place B which is 150 km away. Again he returns to the place A by increasing the speed of the car 10km/ hour and there by reaches 30 minutes earlier than the time taken in his forward journey. Find the total time taken by him in forward and return journey.

Answer 1

Answer:

The total time required in the entire journey is 5.5 hours.

Step-by-step explanation:

Distance= 150km

Let the original speed be S, so the new speed is S+10

Original time = 150/S

New time = 150/( S+10)

Difference between both the time taken= 30 minutes or 1/2 hours.

So, according to the given conditions, we can form the equation as:

150/S - 150/( S+10) = 1/2

So, by solving this we get the equation:

S2+ 10S- 3000= 0

So, on solving it, we get S as 50

Original speed is 50km/hour , so new speed is 60 km/hour

So, original time is 150/50 = 3hours

New time is 150/60 = 2.5 hours

So, total time taken = 5.5 hours.

Answer 2

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