Question

A man driving a scooter at 30 kmph reaches his destination 7 minutes late to
an appointment. If he had drive at 40 kmph he would have reached his destination 3 minutes before time, then his destination is
a) 20 km
b) 11 km
c) 19 km
d) 22 km​

Answer 1

Answer:

The distance covered is 20 km.

Step-by-step explanation:

Given : A man driving a scooter at 30 kmph reaches his destination 7 minutes late to  an appointment. If he had drive at 40 kmph he would have reached his destination 3 minutes before time.

To find : His destination?

Solution :

Let the time taken be 't'.

Distance covered is 'x'.

A man driving a scooter at 30 kmph reaches his destination 7 minutes late to  an appointment.        

The time taken is $\frac{t+7}{60}$ hour.

Speed is 30 kmph.

Distance covered is $D=S\times T$

$x=30\times \frac{t+7}{60}$

$x=\frac{t+7}{2}$ .....(1)

If he had drive at 40 kmph he would have reached his destination 3 minutes before time.

The time taken is $\frac{t-3}{60}$ hour.

Speed is 40 kmph.

Distance covered is $D=S\times T$

$x=40\times \frac{t-3}{60}$

$x=\frac{2(t-3)}{3}$

$x=\frac{2t-6}{3}$ ......(2)

The distance covered is same so equate (1) and (2),

So, $\frac{t+7}{2}=\frac{2t-6}{3}$

$3(t+7)=2(2t-6)$

$3t+21=4t-12$

$4t-3t=21+12$

$t=33$

Substitute the value of t in equation (1),

$x=\frac{33+7}{2}$

$x=\frac{40}{2}$

$x=20$

Therefore, The distance covered is 20 km.