Question

A man driving at 2/3rd of his original speed reaches his destination 30 minutes late later than the usual time then the usual time is

Answer 1

Usual time taken will be 60 minutes

Explanation:

Let the old speed of the man is $v_{old}$

According to question new speed $v_{new}=\frac{2}{3}v_{old}$

$\frac{v_{old}}{v_{new}}=\frac{3}{2}$

As we know that velocity is inversely proportional to the time taken

So $\frac{t_{old}}{t_{new}}=\frac{2}{3}$-----eqn 1

Now it is given that he reach the destination 30 minutes later

Means difference between old time and new time is 30 minutes

From equation 1 difference of time is 1

As 1 is equal to 30 minutes

So 2 will be equal to 60 minutes

So usual time will be equal to 60 minutes

Learn more

A man with 3/5 of his usual speed reaches the destination in2*1/2 hours late .find his usual time to reach the destination

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