Question

A man drops 10 kg rock from 5 m height .What is its speed just before it hits the ground ?

Answer 1

Answer:

Step-by-step explanation:

Mass = 10 kg

Height = 5 m

so, by equation of position velocity relation

v² - u² = 2 as

u = 0 m/s

a = g =10 m/s²

s = h = 5 m

so, velocity just before hitting the ground = 10 m/s