A man drops a 10 kg rock from the top of a 5 m ladder.What is its kinetic energy when it reaches the ground?What is its speed just before it hits the ground?
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Answered by
19
mass=10kg
height=5
since kinetic energy=potential energy
So
k.e.=mgh
=10(9.8)(5)=490j
from eqn 1
mgh=1/2mv2
=v2=2(10)(5)
=v2=100
v=√100
v=10m/s
height=5
since kinetic energy=potential energy
So
k.e.=mgh
=10(9.8)(5)=490j
from eqn 1
mgh=1/2mv2
=v2=2(10)(5)
=v2=100
v=√100
v=10m/s
khushidhir:
thanks
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5
✨Hey✨
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