A man drops a 10 kg rock from the top of a 5 m ladder.what is its kinetic energy when reaches the ground? What is itd dpeed just before it hits the ground?
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Velocity with which it will hit the ground :
v^2 - u^2 = 2gs
v^2 = 2 *10 *5 = 100
v = 10 m/ s
Kinetic Energy when the ball reaches the ground = 1/2 mv^2 = 1/2 *10*10^2
= 500 J
v^2 - u^2 = 2gs
v^2 = 2 *10 *5 = 100
v = 10 m/ s
Kinetic Energy when the ball reaches the ground = 1/2 mv^2 = 1/2 *10*10^2
= 500 J
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