A man drops a 10kg Rock from The top of a 5 m ladder.What is the kinetic energy when it reaches the ground?What is its speed just before it hits the ground?
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As whole of the energy will be converted to kinetic so applying conservation of energy theorem we get ••••
Kinetic energy = potential energy
= Mgh
= 10×10×5 ( let g =10 instead of 9.8 to make calculation easier)
=500 j
So kinetic energy is 500 j approx
Then
For velocity ______
1/2 m (v)sq = kinetic energy
1/2 ×10 × vsq = 500
V sq = 100
V = 10 m/s
Hope it was helpful
Plz Mark brainliest
Kinetic energy = potential energy
= Mgh
= 10×10×5 ( let g =10 instead of 9.8 to make calculation easier)
=500 j
So kinetic energy is 500 j approx
Then
For velocity ______
1/2 m (v)sq = kinetic energy
1/2 ×10 × vsq = 500
V sq = 100
V = 10 m/s
Hope it was helpful
Plz Mark brainliest
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