a man drops a 10kg rock from the top of a 5m ladder.when it reaches the ground, find kinetic energy and speed are respectively.
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Answer: K.E. at bottom = 500 J
v = √100 = 10 m/s
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Explanation:
[A] K.E. at bottom = P.E at top
K.E. at bottom = mgh
K.E. at bottom = 10 × 10 × 5
K.E. at bottom = 500 J
[B] K.E. at bottom = 1/2 mv²
500 = 1/2 × 10 × v²
v² = 100
v = √100 = 10 m/s
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