a man drops a 50 kg stone from the top of a ladder of length 10 m which is at a height of 5m above the ground.what is its kinetic energy when it reaches the ground?
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✨solution:-
✨Mass = 10 kg
Height = 5 m
so, by equation of position velocity relation
v² - u² = 2as
u = 0 m/s
a = g =10 m/s²
s = h = 5m
so, velocity just before hitting the ground = 10 m/s
and the kinetic energy = 1/2 mv² = 500 J✨
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✨Mass = 10 kg
Height = 5 m
so, by equation of position velocity relation
v² - u² = 2as
u = 0 m/s
a = g =10 m/s²
s = h = 5m
so, velocity just before hitting the ground = 10 m/s
and the kinetic energy = 1/2 mv² = 500 J✨
✨❤❤!!mark me brainleist!!❤❤✨
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