a man earns a fixed monthly salary and a fixed increments if after 4years his salary was rupee1500 and 10years after ruppes 1800 what was its initial salary
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Step-by-step explanation:
Let the starting salary of the man be Rs. x and the fixed annual increment be Rs. y. Then,
Salary after 4 years of service =Rs. (x+4y)
Salary after 10 years of service =Rs. (x+10y)
∴x+4y=1500 (i)
x+10y=1800 (ii)
Substracting equation (i) from equation (ii), we get
6y=300⇒y=50
Putting y=50 in equation (i), we get x=1300.
Hence the starting salary was Rs. 1300 and annual increment is Rs. 50
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