A man earns Rs 600 per month than his wife. One tenth of the man salary and one sixth of wife's salary amounts to rs 1500 , which is save every month. Find their incomes.
Answers
✬ Man = Rs 6000 ✬
✬ Wife = Rs 5400 ✬
Step-by-step explanation:
Correct Question: A man earns Rs 600 per month more than his wife. One tenth of the man's salary and one sixth of wife's salary amounts to rs 1500 , which is saved every month. Find their incomes.
Given:
- A man earns Rs 600 more than his wife.
- One tenth of man's and one sixth of wife's salary amounts to Rs 1500.
To Find:
- What is income of each person?
Solution: Let the salary of wife be Rs x. Therefore,
➟ Salary of man = 600 more than x
➟ Man's salary = Rs (x + 600)
A/q
- One tenth of man's salary = 1/10(x + 600)
- One sixth of wife's salary = 1/6(x)
1/10(x + 600) + 1/6(x) = 1500
x + 600/10 + x/6 = 1500
3(x + 600) + 5x/30 = 1500
3x + 1800 + 5x = 1500 × 30
8x + 1800 = 45000
8x = 45000 – 1800
8x = 43200
x = 43200/8
x = 5400
So income of
➬ Wife is x = Rs 5400
➬ Man is 5400 + 600 = Rs 6000
Answer:
Given:
A man earns Rs 600 more than his wife.
One tenth of man's and one sixth of wife's salary amounts to Rs 1500.
To Find:
What is income of each person?
Solution: Let the salary of wife be Rs x. Therefore,
➟ Salary of man = 600 more than x
➟ Man's salary = Rs (x + 600)
A/q
One tenth of man's salary = 1/10(x + 600)
One sixth of wife's salary = 1/6(x)
⟹ 1/10(x + 600) + 1/6(x) = 1500
⟹ x + 600/10 + x/6 = 1500
⟹ 3(x + 600) + 5x/30 = 1500
⟹ 3x + 1800 + 5x = 1500 × 30
⟹ 8x + 1800 = 45000
⟹ 8x = 45000 – 1800
⟹ 8x = 43200
⟹ x = 43200/8
⟹ x = 5400
So income of
➬ Wife is x = Rs 5400
➬ Man is 5400 + 600 = Rs 6000