A man enters a lift at the 20th floor of a 40 storey building and stands on a weighing scale which shows a reading of 600 N. When the lift door is closed, the scales read720 N for the first 5 seconds, 600 N for the next 20 seconds and then 480 N for the next 5 seconds after which the lift door is opened. Which of the following statements is correct?
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Answer:
Mass of the man m=40kg
Acceleration of lift in upward direction a=2m/s
2
Let the weight shown by machine be N.
Equation of motion for the body : ma=N−mg
We get N=m(a+g)
∴ N=(40)(2+10)=480 N
Thus weight of the man recorded by machine W
′
=
g
N
∴ W
′
=
10
480
=48 kg
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