A man exerts a maximum force of 400 N. He has
to pull a mass of 150 kg to a height of 1.5 m by
using an inclined plane. The inclined plane has
efficiency of 80%. What should be the minimum
length of the plane? Use g = 10 m/s2.
[Ans: 7 m]
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Answer:
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answer is 7m but my answer is coming 7.03m
I have explain line by line
please mark be
Explanation:
given,
effort= 400N
mass=150kg
g=10m/S2
load= mg
=150×10
= 1500N
height= 1.5m
efficiency= 80%
we know,
efficiency= output work / input work × 100%
or, 80%= l×h/e×l × 100%
or,80= 1500×1.5/400×l. ×100%
or, 400×80=1500 ×1.5 ×100
or, 32000l= 225000
or, l= 32000/225000
or, l= 7.03m
proved
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