A man falls from top of the building of 30 mtrs. the body of man and building is 6 mtrs away then find the speed of the man who was falling?
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Step-by-step explanation:
g=GM/R^2
=9.8 m/s^2
v^2=u^2+2gh
=0+2(9.8)(30)
v^2=588
On taking square root on both sides.
v=24.25 m/s.
The speed of man falling will be 24.25 m/s.
(The body of man and building is 6m away means he jumps such that ,when he falls he will fall 6m away from building.)(This will anyhow not affect the falling speed of the man)
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