Math, asked by aamir44, 11 months ago

. A man finishes a work in 18 days and b
can do the same work in half the time
taken by A. Then working together, what
part o the same work they can finish in a
day?

Answers

Answered by Anonymous
0

A's 1 day work = 1/18

B's 1 day work = 1/9 [because B take half time than A]

(A+B)'s one day work =

= (\frac{1}{18}  + \frac{1}{9} )

= (\frac{1 + 2}{18} )

= \frac{3}{18}

= \frac{1}{6}

So in one day 1/6 work will be done.


Anonymous: Please mark me brainliestt
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