Question

. A man finishes a work in 18 days and b
can do the same work in half the time
taken by A. Then working together, what
part o the same work they can finish in a
day?
​

Answer 1

A's 1 day work = 1/18

B's 1 day work = 1/9 [because B take half time than A]

(A+B)'s one day work =

$= (\frac{1}{18}  + \frac{1}{9} )$

$= (\frac{1 + 2}{18} )$

$= \frac{3}{18}$

$= \frac{1}{6}$

So in one day 1/6 work will be done.

Answer 2

A is taking time 18

B is taking time 9

average = 9+18÷2

=27÷2

=13 days