Question

A man fires a bullet of 200 gat a speed of 5 m/s which is at rest for an interval of 3 second , then impulse is​

Answer 1

Answer:

Impulse and momentum conservation

Explanation:

★ Given ;

» Mass of bullet = 200 gram = 0.2 Kg

» Velocity of bullet = 5 m / s

» Time interval = 3 seconds

★ We know that ;

IMPULSE ( I ) = ∆ P / ∆ t = Change in momentum / time

» Impulse = mass × Velocity / time

= 0.2 × 5 / 3

= 1 / 3

Impulse = 1 / 3 = 0.33 Kg m / s

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