Question

A man fires a bullet of mass 200g at a Speed
of 5m/s .
The gun is of one
Kg mass. By
what velocity the gun rebounds back word ?​

Answer 1

Answer:

1 ms^-1

Explanation:

formula:

mu+m'u'=mv+m'v'

Answer 2

Given

Mass of bullet = 200 g = 0.2 kg

Velocity of bullet = 5 m/s

Mass of gun = 1 kg

To Find

Velocity of gun

Solution

We know that

Law of conservation of linear momentum

$\red{\sf \longrightarrow m_{1}v_{1}=-m_{2}v_{2}}$

Here

• m₁ = Mass of bullet
• m₂ = Mass of gun
• v₁ = Velocity of bullet
• v₂ = Velocity of gun

Units

• m = kg
• v = m/s

According to the question

We are asked to find velocity of gun

Therefore

We must find "v₂"

Hence

$\green{\sf \longrightarrow v_{2}=-\dfrac{m_{1}v_{1}}{m_{2}}}$

Given that

Mass of bullet = 200 g = 0.2 kg

Velocity of bullet = 5 m/s

Mass of gun = 1 kg

Hence

• m₁ = 200 g = 0.2 kg
• v₁ = 5 m/s
• m₂ = 1 kg

Substituting the values

We get

$\orange{\sf \longrightarrow v_{2}=-\dfrac{0.2 \times 5}{1} \ m/s}$

Therefore

$\purple{\sf \longrightarrow v_{2}=-1 \ m/s}$

Hence

Velocity of gun = - 1 m/s