Question

A man fires a bullet of mass 200g at a Speed
of 5m/s .
The gun is of one
Kg mass. By
what velocity the gun rebounds back word ?​​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

mass of bullet, m1= 200 g = 0.2 kg

mass of gun, m2= 1 kg

velocity of bullet, V1= 5 m/s

velocity of GUN, V2= ?

According to law of conservation of linear momentum,

Linear momentum=Linear momentum

before firing after firing

=>. 0 = m1 V1 + m2 V2

=>. V2 = - m1 V1/m2

=>. - 0.2×5×1

=>. V2 = - 1 m/s

Therefore, velocity of the gun = -1 m/s.

All the best

Hope this helps