Question

a man freely fall stand on a weighing machine. what will be the weight shown by the machine

Answer 1

$\textbf{ Hello Mate! }$

Thanks for this question!

This is most popular and interesting fact to show weight is the force of gravity applied by us on ground and can vary from place to place.

When the man standing on weighing machine is falling freely then the weight will be "0" because during this period body is not exerting force on ground and body has free acceleration.

Let's understand briefly, go through once "attatchment". Here lift is going downwards

Here, mg = ( mass ) × ( acceleration due to gravity )

ma = ( mass ) × ( acceleration by life )

R = reaction force ( opposite of actionary force made by man on weighing machine )

By formula => mg - R = ma

mg - ma = R

m( g - a ) = R

Now, assume that suddenly that rope breaks and lift starts going downwards.

At that time => g = a

Hence,

m( g - g ) = R

m(0) = R or R ( reactionary force ) = 0

When reactionary force is "0" then force applied on machine also is "0" and therefore weight will also be "0".

$\boxed{ Weight\:of\:body\:will\:be\:0 }$

Have great future ahead!