Question

a man from his total savings gave 1/3 to his daughter and 3/4 of the remaining to his wife he had till rupees 20000 left with him find his total savings


PLEASE GIVE STEP BY STEP EXPLANATION​

Answer 1

Answer:let his total savings = X

then 1/3 of X = X/3

now remaining saving = X-(X/3)

so money given to his wife = 3/4{X-(X/3)}

=3/4{(3X-X)/3}

= 3/4{2X/3}

= X/2

and remaining = 20,000

now by adding we get

X= X/3+X/2+20,000

X-X/3-X/2 = 20,000

by taking LCM of 2 &3 we get 6

so (6X-2X-3X)/6 =20,000

by solving we get X/6 = 20,000

X= 20,000x 6

X=120000

so total saving = 120000

Step-by-step explanation:hope it helps

Answer 2

Answer:

15000 to his wife

3750 to his daughter

Step-by-step explanation:

first multiply

20000 x (3/4) = 15000 to wife

then to daughter

15000 x (1/3) = 3750 to daughter