a man gave 2/3 of his property to his wife and divided the remaining property equally among his two children . what part of the full property was given to each child
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Answered by
5
Answer:
1/6 part
Step-by-step explanation:
Let the total property be x
2/3 given to wife = 2/3 of x =2x/3
Now remaining property = x - 2x/3
= x/3
Now it is divided between two sons equally = x/3 ÷ 2
= x/3 × 1/2
= x/6
Now, Part of whole property given to sons
= x/6 of x
= x/6 × x
=6
Answered by
0
The property given to wife :2/3
Property given to two children equally: 2/3 x-(x+x):x
2/3x-2x:x
2/3x:3x
=3x-2/3x
Lcm as 3
9/3x-2/3x
= 7/3x
(7/3)/2
2.5/2 =25/20
Each child gets 25/20 share
Mate this is the correct answer
Hope this helps you
Property given to two children equally: 2/3 x-(x+x):x
2/3x-2x:x
2/3x:3x
=3x-2/3x
Lcm as 3
9/3x-2/3x
= 7/3x
(7/3)/2
2.5/2 =25/20
Each child gets 25/20 share
Mate this is the correct answer
Hope this helps you
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