Math, asked by prabhagupta319, 7 months ago

a man gave 2/3 of his property to his wife and divided the remaining property equally among his two children . what part of the full property was given to each child​

Answers

Answered by debasishbiswal790
5

Answer:

1/6 part

Step-by-step explanation:

Let the total property be x

2/3 given to wife = 2/3 of x =2x/3

Now remaining property = x - 2x/3

= x/3

Now it is divided between two sons equally = x/3 ÷ 2

= x/3 × 1/2

= x/6

Now, Part of whole property given to sons

= x/6 of x

= x/6 × x

=6

Answered by popurivedagna
0
The property given to wife :2/3
Property given to two children equally: 2/3 x-(x+x):x
2/3x-2x:x
2/3x:3x
=3x-2/3x
Lcm as 3
9/3x-2/3x
= 7/3x
(7/3)/2
2.5/2 =25/20
Each child gets 25/20 share

Mate this is the correct answer
Hope this helps you
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