Math, asked by riyalove82, 10 months ago

A man gave 2/3of his property to jis wife and divided the remaining property equally among his two childres . what part of the full property was given to each child​

Answers

Answered by Amankhare
1
1-2/3
1/3


each got 1/6 th part

riyalove82: please explain the answer with statements
Answered by Anonymous
8
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\sf{\underline{Given:}}


\sf{No.\:of\:properties} = 1

\sf{Property\:(Wife)} = \frac{2}{3}


\sf{Now,}

\sf{Remaining\:property}

 = 1 - \frac{2}{3} = \frac{1}{3}


\sf{And,\:we\:also\:know\:that:}

He divided the remaining property, equally among his two children.


\sf{So,}

\sf{Each\:child}

 = \frac{1}{3} \times \frac{1}{2}

 = \frac{1}{5}


\sf{\underline{Therefore,}}

 \frac{1}{5} of total property was given to each child.


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riyalove82: but the answer is wrong
Anonymous: What is the answer?
Anonymous: 1/6..?
riyalove826: yeah
Anonymous: Ohh
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