Question

a man gave 2/5 of his property to his son, 1/3 of his property to his daughter, and the rest of his wife. what fraction of the property did the wife get?​

Answer 1

15/15= 1 whole

2/5+1/3=

6/15+5/15=15/15

11/15=15/15

15-11=4

4/15 is wife's fraction

Answer 2

A man gave $\sf{\frac{2}{5}}$ of his property to his son.

→ Property of son = $\sf{\frac{2}{5}}$

Also, he gave $\sf{\frac{1}{3}}$ of his property to his daughter.

→ Property of daughter = $\sf{\frac{1}{3}}$

Rest of his property he gave to his wife.

We have to find the fraction of the property of his wife.

Property of wife = Remaining property.

So,

Remaining property = 1 - (Property ofson + property of daughter)

i.e.

→ $\sf{1\:-\:(\dfrac{2}{5}}$ + $\sf{\dfrac{1}{3})}$

→ $\sf{1\:-\:(\dfrac{6\:+\:5}{15})}$

→ $\sf{1\:-\:\dfrac{11}{15}}$

→ $\sf{\dfrac{15\:-\:11}{15}}$

→ $\sf{\dfrac{4}{15}}$

•°• Property of his wife is 4/15