A man gave 35% of his money to his son and 40% of the amount to his daughter. If he is left with Rs23400, find how much money was there with him originally.
Answers
Let the amount of money he had be Rs. x.
Amount of money he gave to his eldest son=25% of Rs. x=Rs. (x/4)
Amount of money he gave to his younger son=20% of Rs. x=Rs. (x/5)
Amount of money left=Rs.{x-(x/4)-(x/5)}=Rs.(11/20)x
Amount of money he gave to his daughter =20% of Rs. (11/20)x=Rs. (11x/100)
Amount of money left=Rs.(11x/20)-Rs. (11x/100)=Rs. (11x/25)
Amount of money left was given by him to his wife=Rs. 880
=>11x/25=880
=>x=2000
:. He originally had Rs.2000.
Now, amount of money received by his eldest son=Rs(x/4) =Rs. 500
amount of money received by his younger son=Rs(x/5) =Rs. 400
Amount of money he gave to his daughter =Rs. (11x/100)=Rs. 220
:. Ratio of the money received by his eldest son, younger son and daughter=500:400:220=25:20:11
Hi,
Let the salary earned by the man be x
So he gave to the son = 35% of x
He is left with ( x-35x / 100)= 65x/100
The salary given to daughter is (65x / 100 )(40/100)=26x/100
He is left with 65x/100 -26x/100 =39x/100
It is given that he is left with Rs 23400 = 39x/100
∴39x / 100 = 23400
ð X = 23400 × 100/39 = Rs 60000
∴He had originally Rs 60000