Math, asked by sree31395, 11 months ago

a man gave 7/15 of his property to his wife and 4/15 to his daughter and the remaining to his son.what part of the property did his his son receive?​

Answers

Answered by gayatri789
4

Answer:

7/15-4/15

answer:subtract both the numbers anwers is

3/15

Answered by arharith
3

Answer:

Step-by-step explanation:

amt of property the man gave to his wife=7/15

amt of property the man gave to his daughter=4/15

total amt of property the man had=15/15

amt of property the man gave to his son=15/15-(7/15+4/15)

=15-11/15

4/15

therefore the man gave away 4/15 th of his property to his son

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