Question

a man gave half of his property to his eldest son 1/4 of his property to his 2nd son .1/8 of his property to his third son and the remaining of his property was given to the youngest son. what fraction of his property was given to the youngest son?

Answer 1

$1-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\right)\\~\\=1-\left(\frac{4}{8}+\frac{2}{8}+\frac{1}{8}\right)\\~\\=1-\frac{4+2+1}{8}\\~\\=1-\frac{7}{8}\\~\\=\frac{1}{8}$

The youngest son gets $\boxed{\frac{1}{8}}$ of the property.

Answer 2

Part given to 1st and 2nd and 3rd  son=
1/4+1/8+1/2
=(2+1+4)/8
=7/8
Remaining part=
1-7/8=1/8 
It was given to the youngest son (assuming that he has 4 sons in total).
Ans:The part given to the youngest son is 1/8.