Question

A man gets 25% of the amount of money with him to his eldest son 20 person to his younger son and 20 percent of remainder to his daughter and the rest 880 to his wife find the amount of money he had with him and also find the ratio of the money received by his son to his younger son and his daughter

Answer 1

Answer:

Let the amount of money he had be Rs. x.

Amount of money he gave to his eldest son=25% of Rs. x=Rs. (x/4)

Amount of money he gave to his younger son=20% of Rs. x=Rs. (x/5)

Amount of money left=Rs.{x-(x/4)-(x/5)}=Rs.(11/20)x

Amount of money he gave to his daughter =20% of Rs. (11/20)x=Rs. (11x/100)

Amount of money left=Rs.(11x/20)-Rs. (11x/100)=Rs. (11x/25)

Amount of money left was given by him to his wife=Rs. 880

=>11x/25=880

=>x=2000

:. He originally had Rs.2000.

Now, amount of money received by his eldest son=Rs(x/4) =Rs. 500

amount of money received by his younger son=Rs(x/5) =Rs. 400

Amount of money he gave to his daughter =Rs. (11x/100)=Rs. 220

:. Ratio of the money received by his eldest son, younger son and daughter=500:400:220=25:20:11