Question

A man gets an employment of Rs.1000per month with an annual increment of Rs.50 . What does he earn in 10 years​

Answer 1

Answer:

in 10 years, no:of months is 10×12=120months

total amount = 120×1000 = 120000

annual increment = 50×10 = 500

=>total salary = 120500

Answer 2

Answer:

Rs.37000

Explanation:

Given :

• A man gets an employment of Rs.1000per month with an annual increment of Rs.50

To Find :

• Earning of the man in 10 years.

Solution :

$\sf{}Present\ salary= Rs\ 1000\ per\ month$

$\sf{}Annual\ salary\ in\ first\ year=12\times1000=Rs.\ 12000$

$\sf{}Increment\ every\ year=Rs\ 50$

$\sf{}Annual\ salary\ in\ second\ year=12\times1050= Rs.\ 12600$

$\sf{}So,\ a =12000,d=Rs.\ 600\ and\ n= 10years$

$\sf{}S_n=\dfrac{n}{2}[2a+(n-1)d]$

$\sf{} \implies \dfrac{10}{2}[2\times1000+(10-1)600]$

$\sf{} \implies \dfrac{5}{1}[2000+(9)600]$

$\sf{} \implies 5(2000+ 5400)$

$\sf{} \implies 5(7400)$

$\sf{}\therefore Rs. 37000$

Hence,earning of the man in 10 years is equal to Rs. 37000